20y^2+y-12=0

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Solution for 20y^2+y-12=0 equation:


Simplifying
20y2 + y + -12 = 0

Reorder the terms:
-12 + y + 20y2 = 0

Solving
-12 + y + 20y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-4 + -5y)(3 + -4y) = 0

Subproblem 1

Set the factor '(-4 + -5y)' equal to zero and attempt to solve: Simplifying -4 + -5y = 0 Solving -4 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -5y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -5y = 0 + 4 -5y = 0 + 4 Combine like terms: 0 + 4 = 4 -5y = 4 Divide each side by '-5'. y = -0.8 Simplifying y = -0.8

Subproblem 2

Set the factor '(3 + -4y)' equal to zero and attempt to solve: Simplifying 3 + -4y = 0 Solving 3 + -4y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4y = 0 + -3 -4y = 0 + -3 Combine like terms: 0 + -3 = -3 -4y = -3 Divide each side by '-4'. y = 0.75 Simplifying y = 0.75

Solution

y = {-0.8, 0.75}

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